document.write( "Question 176670: .66x-.75y=-8
\n" ); document.write( ".33x+.5y=17
\n" ); document.write( "How do you solve by substitution?
\n" ); document.write( "Show work?
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Algebra.Com's Answer #131815 by checkley75(3666)\"\" \"About 
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.66x-.75y=-8
\n" ); document.write( ".33x+.5y=17
\n" ); document.write( "First you need to represent eith the x or the y unknown in terms of the other unknown.
\n" ); document.write( ".33x=17-.5y
\n" ); document.write( "x=(17-.5y)/.33
\n" ); document.write( "Now replace x in the other equation with (17-5y)/.33 & solve for y.
\n" ); document.write( ".66(17-.5y)/.33-.75y=-8
\n" ); document.write( "2(17-.5y)-.75y=-8
\n" ); document.write( "34-y-.75y=-8
\n" ); document.write( "-1.75y=-8-34
\n" ); document.write( "-1.75y=-42
\n" ); document.write( "y=-42/-1.75
\n" ); document.write( "y=24 ans.
\n" ); document.write( "x=(17-.5*24)/.33
\n" ); document.write( "x=(17-12)/.33
\n" ); document.write( "x=5/.33
\n" ); document.write( "x=15.1515
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