document.write( "Question 176670: .66x-.75y=-8
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document.write( ".33x+.5y=17
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document.write( "How do you solve by substitution?
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document.write( "Show work? \n" );
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Algebra.Com's Answer #131815 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .66x-.75y=-8 \n" ); document.write( ".33x+.5y=17 \n" ); document.write( "First you need to represent eith the x or the y unknown in terms of the other unknown. \n" ); document.write( ".33x=17-.5y \n" ); document.write( "x=(17-.5y)/.33 \n" ); document.write( "Now replace x in the other equation with (17-5y)/.33 & solve for y. \n" ); document.write( ".66(17-.5y)/.33-.75y=-8 \n" ); document.write( "2(17-.5y)-.75y=-8 \n" ); document.write( "34-y-.75y=-8 \n" ); document.write( "-1.75y=-8-34 \n" ); document.write( "-1.75y=-42 \n" ); document.write( "y=-42/-1.75 \n" ); document.write( "y=24 ans. \n" ); document.write( "x=(17-.5*24)/.33 \n" ); document.write( "x=(17-12)/.33 \n" ); document.write( "x=5/.33 \n" ); document.write( "x=15.1515 \n" ); document.write( " \n" ); document.write( " |