document.write( "Question 24730: How many gallons of a 30 percent alcohol solution must be mixed with 10 gallons of a 50 percent alcohol solution to make a 40 percent alcohol solution? The equation is ((( Amount x Concentration = Quantity))) \n" ); document.write( "
Algebra.Com's Answer #13177 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Since 30% = 30x \n" ); document.write( "Since 10 gallon of 50% = 50(10-x) \n" ); document.write( "Total = 40(10) \n" ); document.write( "Add it together: \n" ); document.write( "30x+50(10-x)=40(10) \n" ); document.write( "30x+500-50x=400 \n" ); document.write( "-20x=-100 \n" ); document.write( "x = 5 \n" ); document.write( "Hence, there should be about 5 gallons of 30%. \n" ); document.write( "Paul. \n" ); document.write( " |