document.write( "Question 176676: There is a total of 25 coins in Nickles, Dimes, and Quarters. There are four times as many dimes as quarters. The total vaule of the change is $2.05, how many of each coin is there?\r
\n" ); document.write( "\n" ); document.write( "I have tried a few equations:
\n" ); document.write( "1) 5(x-5)+10(4x)+25(x+15)=205
\n" ); document.write( "2) 5(x-20)+10(4x-15)+25x=205
\n" ); document.write( "3) 5x+10(4x)+25x+=205\r
\n" ); document.write( "\n" ); document.write( "I know this can be solved with multiple variables, but I am suppose to solve it with one. Please help.
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Algebra.Com's Answer #131751 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"n\"= number of nickels
\n" ); document.write( "Let \"d\"= number of dimes
\n" ); document.write( "Let \"q\"= number of quarters
\n" ); document.write( "given:
\n" ); document.write( "(1) \"n+%2B+d+%2B+q+=+25\"
\n" ); document.write( "(2) \"d+=+4q\"
\n" ); document.write( "In pennies:
\n" ); document.write( "(3) \"5n+%2B+10d+%2B+25q+=+205\"
\n" ); document.write( "There are 3 equations and 3 unknowns, so it's solvable
\n" ); document.write( "Multiply (1) by \"5\" and subtract from (3)
\n" ); document.write( "\"5n+%2B+10d+%2B+25q+=+205\"
\n" ); document.write( "\"-5n+-+5d+-+5q+=+-125\"
\n" ); document.write( "--------------------------
\n" ); document.write( "\"5d+%2B+20q+=+80\"
\n" ); document.write( "And using (2),
\n" ); document.write( "\"5%2A4q+%2B+20q+=+80\"
\n" ); document.write( "\"40q+=+80\"
\n" ); document.write( "\"q+=+2\"
\n" ); document.write( "\"d+=+4q\"
\n" ); document.write( "\"d+=+8\"
\n" ); document.write( "(1) \"n+%2B+d+%2B+q+=+25\"
\n" ); document.write( "\"n+%2B+8+%2B+2+=+25\"
\n" ); document.write( "\"n+=+15\"
\n" ); document.write( "There are 15 nickels, 8 dimes and 2 quarters
\n" ); document.write( "check:
\n" ); document.write( "(3) \"5n+%2B+10d+%2B+25q+=+205\"
\n" ); document.write( "\"5%2A15+%2B+10%2A8+%2B+25%2A2+=+205\"
\n" ); document.write( "\"75+%2B+80+%2B+50+=+205\"
\n" ); document.write( "\"205+=+205\"
\n" ); document.write( "OK
\n" ); document.write( "
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