document.write( "Question 176667: Using the product property simplify the
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\n" ); document.write( "\n" ); document.write( "1.)the square root of 52
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Algebra.Com's Answer #131726 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\"sqrt%2852%29\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "The goal of simplifying expressions with square roots is to factor the radicand into a product of two numbers. One of these two numbers must be a perfect square. When you take the square root of this perfect square, you will get a rational number.\r
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\n" ); document.write( "\n" ); document.write( "So let's list the factors of 52\r
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\n" ); document.write( "\n" ); document.write( "Notice how 4 is the largest perfect square, so lets factor 52 into 4*13\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%284%2A13%29\" Factor 52 into 4*13
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\n" ); document.write( "\"sqrt%284%29%2Asqrt%2813%29\" Break up the square roots using the identity \"sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29\"
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\n" ); document.write( "\"2%2Asqrt%2813%29\" Take the square root of the perfect square 4 to get 2
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\n" ); document.write( "So the expression \"sqrt%2852%29\" simplifies to \"2%2Asqrt%2813%29\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we evaluate the square root of 52 with a calculator we get\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2852%29=7.21110255092798\"\r
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\n" ); document.write( "\n" ); document.write( "and if we evaluate \"2%2Asqrt%2813%29\" we get\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Asqrt%2813%29=7.21110255092798\"\r
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\n" ); document.write( "\n" ); document.write( "This shows that \"sqrt%2852%29=2%2Asqrt%2813%29\". So this verifies our answer
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