document.write( "Question 24710: In 15 years, Maya will be twice as old as David is now. In 15 years David will be as old as Maya will be 10 years from now. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #13172 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Read these carefully \n" ); document.write( "d = David's age now \n" ); document.write( "m = Maya's age now \n" ); document.write( "(1) m + 15 = 2 * d \n" ); document.write( "(2) d + 15 = m + 10 \n" ); document.write( "from (1) \n" ); document.write( "d = (m + 15) / 2 \n" ); document.write( "substituting this in (2) \n" ); document.write( "(m + 15)/2 + 15 = m + 10 \n" ); document.write( "multiply through by 2 \n" ); document.write( "m + 15 + 30 = 2 * m + 20 \n" ); document.write( "subtract m from both sides \n" ); document.write( "subtract 20 from both sides \n" ); document.write( "m = 25 \n" ); document.write( "d = (25 + 15) / 2 \n" ); document.write( "d = 20 \n" ); document.write( "check \n" ); document.write( "20 = (25 + 15) / 2 \n" ); document.write( "OK \n" ); document.write( "25 + 15 = 2 * 20 \n" ); document.write( "OK \n" ); document.write( " |