document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176631>Question 176631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ramon mixes 12 liters of 8% acid solution with a 20% acid solution, which results in a 60% acid solution.  Find the number of liters of 20% acid solution in the new mixture. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131705 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131705\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am going to assume that is suppose to be 16 % and not 60% since that isnt possible. It has to fall between 8% and 20% solutions for this to work. You cannot mix two percentage mixtures together and get less than the lowest or greater than the highest amounts.  lets call the amount of 20% solution x.<BR>\n" );
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document.write( ".08(12)+.2(x)=.16(12+x)<BR>\n" );
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document.write( ".96+.2x=1.92+.16x<BR>\n" );
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document.write( ".04x=.96<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=24%29 ALIGN=MIDDLE  ALT=\"highlight%28x=24%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >liters of 20% solution </SPAN>\n" );
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