document.write( "Question 176578: Amy invests a part of $8000 in bonds paying 12% interest. The remainder is in a savings account at 8%. If she receives $840 in interest for 1 year, how much does she have invested at each rate? (Show the two equations you used and then your solution) \n" ); document.write( "
Algebra.Com's Answer #131650 by ptaylor(2198)\"\" \"About 
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\n" ); document.write( "Let x=amount invested at 12%
\n" ); document.write( "And let y=amount invested at 8%\r
\n" ); document.write( "\n" ); document.write( "Now we are told the following:
\n" ); document.write( "x+y=$8000---------------------------------eq1
\n" ); document.write( "0.12x+0.08y=$840-----------------------------eq2\r
\n" ); document.write( "\n" ); document.write( "From eq1, y=$8000-x. Substitute this into eq2 and we have:\r
\n" ); document.write( "\n" ); document.write( "0.12x+0.08($8000-x)=$840 get rid of parens
\n" ); document.write( "0.12x+$640-0.08x=$840 subtract $640 from each side
\n" ); document.write( "0.12x+$640-$640-0.08x=$840-$640 collect like terms
\n" ); document.write( "0.04x=$200 divide each side by 0.04
\n" ); document.write( "x=$5000----------------------------------amount invested at 12%
\n" ); document.write( "substitute x=$5000 into eq1:
\n" ); document.write( "$5000+y=$8000 subtract $5000 from each side
\n" ); document.write( "y=$3000-------------------------------------amount invested at 8%\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.12*$5000+0.08*$3000=$840
\n" ); document.write( "$600+$240=$840
\n" ); document.write( "$840=$840\r
\n" ); document.write( "\n" ); document.write( "Another way------------------------only 1 equation
\n" ); document.write( "Let x=amount invested at 12%
\n" ); document.write( "Then $8000-x=amount invested at 8%
\n" ); document.write( "0.12x+0.08($8000-x)=$840------------------same equation as before\r
\n" ); document.write( "\n" ); document.write( "Does this help???----------ptaylor\r
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