document.write( "Question 176564: An actor invests some money at 9%, and $32000 more than twice the amount at 12%. The total annual interest earned from the investment is $23640. How much did he invest at each amount? Use the six- step method.\r
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document.write( "Please do this step by step so I can see how you got each number. \n" );
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Algebra.Com's Answer #131639 by Mathtut(3670)![]() ![]() ![]() You can put this solution on YOUR website! ok what we are after is amounts invested at 9% and at 12%. Lets call those x and y respectively \n" ); document.write( ": \n" ); document.write( " We are given that y=2x+32000. So lets write our equation, Lets write it verbally first. (The amount invested) at (x times its interest rate) + (the amount invested) at (y times its interest rate) will give us(equals) the total annual interest earned. \n" ); document.write( ": \n" ); document.write( "so we have \n" ); document.write( "x amount investe at 9% \n" ); document.write( "y=2x+32000...eq 1 \n" ); document.write( ": \n" ); document.write( ".09x+.12y=23640...eq 2 \n" ); document.write( ": \n" ); document.write( "take y's value from eq 1 and plug it into eq 2 \n" ); document.write( ": \n" ); document.write( ".09x+.12(2x+32000)=23640 \n" ); document.write( ": \n" ); document.write( ".09x+.24x+3840=23640 \n" ); document.write( ": \n" ); document.write( ".33x=19800 \n" ); document.write( ": \n" ); document.write( "$ \n" ); document.write( ": \n" ); document.write( "$ |