document.write( "Question 176564: An actor invests some money at 9%, and $32000 more than twice the amount at 12%. The total annual interest earned from the investment is $23640. How much did he invest at each amount? Use the six- step method.\r
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Algebra.Com's Answer #131639 by Mathtut(3670)\"\" \"About 
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ok what we are after is amounts invested at 9% and at 12%. Lets call those x and y respectively
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\n" ); document.write( " We are given that y=2x+32000. So lets write our equation, Lets write it verbally first. (The amount invested) at (x times its interest rate) + (the amount invested) at (y times its interest rate) will give us(equals) the total annual interest earned.
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\n" ); document.write( "so we have
\n" ); document.write( "x amount investe at 9%
\n" ); document.write( "y=2x+32000...eq 1
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\n" ); document.write( ".09x+.12y=23640...eq 2
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\n" ); document.write( "take y's value from eq 1 and plug it into eq 2
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\n" ); document.write( ".09x+.12(2x+32000)=23640
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\n" ); document.write( ".09x+.24x+3840=23640
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\n" ); document.write( ".33x=19800
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\n" ); document.write( "$\"highlight%28x=60000%29\"amount invested at 9%
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\n" ); document.write( "$\"highlight%28y=2%2860000%29%2B32000=152000%29\"amount invested at 12%
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