document.write( "Question 176508: Two-thirds of someone's age three years ago plus one sixth of someone's age three years from now will equal someone's age four years ago. How old is someone now? \n" ); document.write( "

Algebra.Com's Answer #131607 by Mathtut(3670) $\"\"$ $\"About$

You can put this solution on YOUR website!
someone's age ....lets call s
\n" ); document.write( ":
\n" ); document.write( "2/3(s-3)+1/6(s+3)=s-4
\n" ); document.write( ":
\n" ); document.write( "(2/3)s-2+(1/6)s+(1/2)=s-4
\n" ); document.write( ":
\n" ); document.write( "4s-12+s+3=6s-24
\n" ); document.write( ":
\n" ); document.write( " $\"highlight%28s=15%29\"$
\n" ); document.write( ":
\n" ); document.write( " \n" ); document.write( "

\n" );