document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176494>Question 176494</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a tall office building, one elevator leaves the third floor and ascends at a speed of 2 floors per second.  Another elevator leaves the 59th floor at exactly the same moment and descends at a speed of 2 floors per second.  If the two elevators do not stop, how long will it take them to pass each other?  At what floor will the elvators pass each other?\r<BR>\n" );
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document.write( "I can solve this problem by subtracting 3 from 59 to get a distance of 56 floors.  Since they are traveling at the same rate divide this by 2 and get 23 floors.  So they would pass at the 26th floor.  23 floors at 2 floors per second would be 11.5 seconds.\r<BR>\n" );
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document.write( "My problem is that I can do all this logically but my teacher wants an equation with variables!  Not sure how to do that.  Thanks for any help!   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131603 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131603\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a tall office building, one elevator leaves the third floor and ascends at a speed of 2 floors per second. Another elevator leaves the 59th floor at exactly the same moment and descends at a speed of 2 floors per second. If the two elevators do not stop, how long will it take them to pass each other? At what floor will the elvators pass each other? <BR>\n" );
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document.write( "Ascending DATA:<BR>\n" );
document.write( "rate = 2 fpsecond ; distance = x floors ; time = d/r = x/2 seconds<BR>\n" );
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document.write( "Decending DATA:<BR>\n" );
document.write( "rate = 2 fpsecond ; distance = (56-x) floors ; time = d/r = (56-x)/2 seconds\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "time = time<BR>\n" );
document.write( "x/2 = (56-x)/2<BR>\n" );
document.write( "x = 56-x<BR>\n" );
document.write( "2x = 56<BR>\n" );
document.write( "x = 28 (# of floors each elemator moves)<BR>\n" );
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document.write( "Ascending: 3 + 28 = 31st floor<BR>\n" );
document.write( "Decending: 59- 28 = 31st floor<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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