document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24572>Question 24572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> this is the question: WRITE AN EQUATION OF THE LINE THAT PASSES THROUGH (3,-5)AND IS PERPENDICULAR TO THE LINE THROUGH (1,4) AND (3,-2). i really nee help. please </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13160 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First of all we need to find the slope of the first line;<BR>\n" );
document.write( "m=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28Y2-Y1%29%2F%28X2-X1%29 ALIGN=MIDDLE  ALT=\"%28Y2-Y1%29%2F%28X2-X1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "m=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-2-4%29%2F%283-1%29 ALIGN=MIDDLE  ALT=\"%28-2-4%29%2F%283-1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "m=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-6%2F2 ALIGN=MIDDLE  ALT=\"-6%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "m=-3<BR>\n" );
document.write( "Now the perpindicular line to this will have a slope that is the opposite reciprocal -3, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "SO the slope of the new line is;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Use the point-slope form to find the equation;<BR>\n" );
document.write( "Y-Y1=m(X-X1)<BR>\n" );
document.write( "y-(-5)=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >(x-3)<BR>\n" );
document.write( "y+5=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x-1<BR>\n" );
document.write( "y=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x-1-5<BR>\n" );
document.write( "So the equation would be;<BR>\n" );
document.write( "y=<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F3 ALIGN=MIDDLE  ALT=\"1%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >x-6<BR>\n" );
document.write( "Hope you understand!<BR>\n" );
document.write( "=) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );