document.write( "Question 176462: can you help with this problem:\r
\n" ); document.write( "\n" ); document.write( "ten gallons of a 30% acid mixture is obtained by mixing a 20% solution with a 50% solution. How much of each must be used?\r
\n" ); document.write( "\n" ); document.write( "i've tried creating two linear equations (one for total volume and one for concentration) but i don't know where to go from there.
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Algebra.Com's Answer #131581 by Mathtut(3670)\"\" \"About 
You can put this solution on YOUR website!
ok lets call the amount of 20% and 50% solutions a and b respectively
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\n" ); document.write( "a+b=10...........eq 1
\n" ); document.write( ".2a+.5b=.3(10)...eq 2
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\n" ); document.write( "rewrite eq 1 to a=10-b and plug this value into eq 2
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\n" ); document.write( ".2(10-b)+.5b=3
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\n" ); document.write( "2-.2b+.5b=3
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\n" ); document.write( ".3b=1
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\n" ); document.write( "\"highlight%28b=3.33%29\"amount of 50% solution
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\n" ); document.write( "\"highlight%28a=10-b=10-3.33=6.67%29\"amount of 20% solution\r
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