document.write( "Question 176433This question is from textbook Algebra 2
\n" ); document.write( ": Solve each equation. Check your awnser\r
\n" ); document.write( "\n" ); document.write( " -5x^-3=0\r
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\n" ); document.write( "\n" ); document.write( "****NOTE***** ^ means squared \n" ); document.write( "

Algebra.Com's Answer #131546 by solver91311(24713) $\"\"$ $\"About$

You can put this solution on YOUR website!
I think you mean: $\"-5x%5E2+-+3+=+0\"$ , rather than $\"-5x%5E-3=0\"$ which is what you wrote.\r
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\n" ); document.write( "\n" ); document.write( "Add $\"3\"$ to both sides:\r
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\n" ); document.write( "\n" ); document.write( " $\"-5x%5E2=3\"$ \r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by $\"-1%2F5\"$ \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2+=+-3%2F5\"$ \r
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\n" ); document.write( "\n" ); document.write( "Take the square root of both sides\r
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or\r
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\r
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\n" ); document.write( "\n" ); document.write( "Now rationalize the denominator:\r
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