document.write( "Question 176427: In the word problem , three consecutive numbers where 3times the first is 4 more than 2 times the second. The answer I came up with is 3z=4+2z+1+z+2. \n" ); document.write( "
Algebra.Com's Answer #131542 by MathTherapy(10557)\"\" \"About 
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In the word problem , three consecutive numbers where 3times the first is 4 more than 2 times the second. The answer I came up with is 3z=4+2z+1+z+2.\r
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\n" ); document.write( "\n" ); document.write( "The real solution to the problem is:\r
\n" ); document.write( "\n" ); document.write( "1st #: z
\n" ); document.write( "2nd #: z + 1
\n" ); document.write( "3rd #: z + 2\r
\n" ); document.write( "\n" ); document.write( "3(z) = 2(z + 1) + 4
\n" ); document.write( "3z = 2z + 2 + 4
\n" ); document.write( "z = 6\r
\n" ); document.write( "\n" ); document.write( "Numbers are 6, 7, & 8
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