document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176382>Question 176382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 2 meters larger than its height.  The diagonal brace measures sqrt 6m.  Find the width and height.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131482 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131482\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 2 meters larger than its height. The diagonal brace measures sqrt 6m. Find the width and height. <BR>\n" );
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document.write( "Let height be \"x\".<BR>\n" );
document.write( "Then width is \"x+2\"<BR>\n" );
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document.write( "Pythagoras says x^2 + (x+2)^2 = (sqrt(6))^2<BR>\n" );
document.write( "x^2 + x^2 + 4x + 4 = 6<BR>\n" );
document.write( "2x^2 + 4x -2 = 0<BR>\n" );
document.write( "x^2 + 2x -1 = 0<BR>\n" );
document.write( "x = [-2 +- sqrt(4 - 4*1*-1)]/2<BR>\n" );
document.write( "x = [-2 +- sqrt(8)]/2<BR>\n" );
document.write( "x = [-1 +- sqrt(2)]<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = -1 + 1.414 = 0.414 meters (height)<BR>\n" );
document.write( "x+2 = 2.414 meters (width)<BR>\n" );
document.write( "===========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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