document.write( "Question 176308: A> 2x-3y+5y=2
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document.write( "B> 3x+2y-z=12
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document.write( "C> x+4y+z=18\r
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document.write( "FIRST STEP IN THE ELIMINATION OF THE VARIABLE Y
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document.write( " A) MULTIPLY EQUATION B BY -2 AAND ADD EQUATIONS B AND C\r
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document.write( " B) MULTIPLY B BY -2 AND ADD EQUAIONS A AND B\r
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document.write( "C) OTHER, IF SO... HOW? \n" );
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Algebra.Com's Answer #131447 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! A> 2x-3y+5y=2 \n" ); document.write( "B> 3x+2y-z=12 \n" ); document.write( "C> x+4y+z=18 \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "FIRST STEP IN THE ELIMINATION OF THE VARIABLE Y \n" ); document.write( "A) MULTIPLY EQUATION B BY -2 AAND ADD EQUATIONS B AND C \n" ); document.write( "B) MULTIPLY B BY -2 AND ADD EQUAIONS A AND B \n" ); document.write( "C) OTHER, IF SO... HOW? \n" ); document.write( "---------------------- \n" ); document.write( "I'll assume you meant 5z in eqn A. \n" ); document.write( "You need to eliminate a variable, y is ok, from 2 eqns using, leaving 2 eqns with 2 unknowns. \n" ); document.write( "Step A is good, gives an eqn in x and z. \n" ); document.write( "Step B is not good, it eliminates x, not y. \n" ); document.write( "----------- \n" ); document.write( "A better choice is to eliminate x, because its coeff in eqn C is 1, making it easy to scale to match eqns A and B. \n" ); document.write( "Whatever variable you choose to eliminate, you have to eliminate in from 2 eqns. \n" ); document.write( "Try eliminating x. Email me if you need more help. (the thank you notes go to my email.) \n" ); document.write( "--------------- \n" ); document.write( "An update: z is even better for elimination, as B and C have one z in them. Just add B and C and z is gone. \n" ); document.write( " |