document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176341>Question 176341</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many kg of corn that cost P40 per kg must be mixed with 10kg of peanut that cost P80 per kg to  make a mixture that cost P55 per kg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131435 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131435\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of corn needed\r<BR>\n" );
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document.write( "Now we know that the value of the corn (40x) plus the value fo the peanuts (10*80) before they are mixed has to equal the value of the final mixture (55*(10+x)).  So our equation to solve is:\r<BR>\n" );
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document.write( "40x+10*80=55(10+x)  get rid of parens<BR>\n" );
document.write( "40x+800=550+55x  subtract 800 and also 55x from each side<BR>\n" );
document.write( "40x-55x+800-800=550-800+55x-55x  collect like terms<BR>\n" );
document.write( "-15x=-250  divide each side by -15<BR>\n" );
document.write( "x=16.667 kg----------------------------amount of corn needed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "16.667*40+10*80=55*26.667<BR>\n" );
document.write( "666.68+800=1466.685<BR>\n" );
document.write( "1466.68=1466.68\r<BR>\n" );
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document.write( "Does this help???-----ptaylor </SPAN>\n" );
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