document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176313>Question 176313</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Deneen bought 120 floor tiles and 3 cans of paint for $195. If a can of paint cost $3.50 more than each tile, find the cost of two cans of paint. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131431 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Deneen bought 120 floor tiles and 3 cans of paint for $195. If a can of paint cost $3.50 more than each tile, find the cost of two cans of paint.\r<BR>\n" );
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document.write( "Cost of 1 tile  =  t         Therefore, cost of a can of paint = t + 3.5\r<BR>\n" );
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document.write( "120t  +  3(t + 3.5) = 195\r<BR>\n" );
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document.write( "120t  + 3t + 10.5   = 195\r<BR>\n" );
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document.write( "123t   =  184.5\r<BR>\n" );
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document.write( "t  =  $1.50\r<BR>\n" );
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document.write( "Since a can of paint costs $3.50 more than 1 tile, then a can of paint costs $1.50 + $3.50 = $5. Therefore, 2 cans of paint cost $10. </SPAN>\n" );
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