document.write( "Question 176318: 4) A student claims “If d does not divide a and d does not divide b, then d does not divide (a+b). How do you respond? Hint look in chapter 4. \n" ); document.write( "

Algebra.Com's Answer #131418 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
The claim is false. Here's a counter-example to show why:\r
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\n" ); document.write( "\n" ); document.write( "Let d=10, a=3, and b=7 (you can pick any random numbers as long as d does not divide either a or b, but it divides the sum)\r
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\n" ); document.write( "\n" ); document.write( "It is true that d does NOT divide a (since 10 does NOT divide 3) and d does NOT divide b (since 10 does NOT divide 7). \r
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\n" ); document.write( "\n" ); document.write( "However, d does divide a+b since 10 divides (3+7) or 10. In other words, $\"10%2F%283%2B7%29=10%2F10=1\"$
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