document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176262>Question 176262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please show me how to use the substitution method to solve this system of equations.\r<BR>\n" );
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document.write( "3x-11y=2<BR>\n" );
document.write( "x-5y=2\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131387 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10555)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x - 11y = 2<BR>\n" );
document.write( " x -  5y = 2 \r<BR>\n" );
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document.write( "x  =  5y - 2\r<BR>\n" );
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document.write( "Substituting this value for x in equation 1, we get:\r<BR>\n" );
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document.write( "3(5y + 2) - 11y = 2<BR>\n" );
document.write( "15y + 6 - 11y = 2<BR>\n" );
document.write( "4y  =  - 4<BR>\n" );
document.write( "y  =  - 1\r<BR>\n" );
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document.write( "x - 5(-1) = 2<BR>\n" );
document.write( "x + 5 = 2<BR>\n" );
document.write( "x = - 3\r<BR>\n" );
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document.write( "Solution: (- 3, - 1)<BR>\n" );
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