document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176226>Question 176226</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the subject area is on imaginary numbers. what is i to the power of 359 equal to. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131322 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131322\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The powers of i go in a cycle of 4:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=i%5E4+=+i%5E2+%2A+i%5E2+=+-1+%2A+-1+=+1+=+i%5E0 ALIGN=MIDDLE  ALT=\"i%5E4+=+i%5E2+%2A+i%5E2+=+-1+%2A+-1+=+1+=+i%5E0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "and so on...\r<BR>\n" );
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document.write( "So, using integer division, divide 359 by 4 and find the remainder.  i raised to the power of 359 is equal to i raised to the power of the remainder when 359 is divided by 4. </SPAN>\n" );
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