document.write( "Question 24645: for the eqation x-square root of x=0 solve for values of x,then graph y=x and y=square root of x \n" ); document.write( "
Algebra.Com's Answer #13131 by quentin252(19)\"\" \"About 
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x - \"sqrt%28x%29\" = 0
\n" ); document.write( "implies x = \"sqrt%28x%29\" (by adding \"sqrt%28x%29\" to both sides of the equation)
\n" ); document.write( "-> x^2 = x (square both sides)
\n" ); document.write( "-> x^2 - x = 0
\n" ); document.write( "-> quadratic equation : (-(-1)+- \"sqrt%28%28-1%29%5E2+-+4%2A1%2A0%29\")/(2*1)
\n" ); document.write( "-> = (1 +- \"sqrt%281%29\")/2 = (1 +- 1)/2 = 0/2 or 2/2 = 0 or 1\r
\n" ); document.write( "\n" ); document.write( "now when graphing simply use intersection pts (0,0) and (1,1)
\n" ); document.write( "y=x is straight line with slope 1
\n" ); document.write( "as for the other, just pick a few points then draw the curve
\n" ); document.write( "(1/2,\"%281%2F2%29%5E2\")=(1/2,\"sqrt%282%29\"/2) is another good pt to start with
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