document.write( "Question 24646: At noon, there were 1000 bacteria in a culture dish. The formula for the growth of the bacteria is n = l000(2a), where n is the number of bacteria, and a is the number of hours the culture has been growing. How many bacteria will there be at 18:00, assuming none of the culture die? a is an exponent.\r
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document.write( "Simplify\r
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document.write( "(k2lm2)(-kn)2 ..the 2's are exponents.\r
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Algebra.Com's Answer #13130 by quentin252(19)![]() ![]() ![]() You can put this solution on YOUR website! okay, so n=1000*(2^a) \n" ); document.write( "and at 18:00 hrs a=6 (since 18:00=6pm is 6 hrs past noon=12:00) \n" ); document.write( "so n=1000*(2^6)=1000*64=64000 at 18:00 hrs.\r \n" ); document.write( "\n" ); document.write( "next, \n" ); document.write( "as above I'll represent exponents with ^ symbol \n" ); document.write( "k^2*l*m^2*(-kn)^2 \n" ); document.write( "order of operations \n" ); document.write( "1. parenthesis: well nothing to do here, \"-kn\" is reduced \n" ); document.write( "2. next exponents \n" ); document.write( " so the k is squared = k^2 \n" ); document.write( " the m (not the lm) is squared = m^2 \n" ); document.write( " and the -kn is squared -- \n" ); document.write( " (-kn)^2=(-k)^2 * n^2 = k^2 * n^2 \n" ); document.write( "3. so now comes the products (left to right) \n" ); document.write( " giving us k^2 * l * m^2 * k^2 * n^2 \n" ); document.write( " grouping the k's gives us : k^4 * l * m^2 * n^2 \n" ); document.write( " or in spiffy notation : \n" ); document.write( " \n" ); document.write( " |