document.write( "Question 175049: A rectangular field is 4 times as long as it is wide. Let the width be x and the length will therefore be 4x. if the length is decreased by 10 in. and the width is increased by 2 in. the perimeter will be 80 in. Find the dimensions of the original field. \n" ); document.write( "

Algebra.Com's Answer #131274 by EMStelley(208) $\"\"$ $\"About$

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\"If the length is decreased by 10 in.\" is the same as saying 4x-10, and \"if the width is increased by 2 in.\" is the same as saying x+2. So the perimeter being 80 is equivalent to
\n" ); document.write( " $\"2%284x-10%29%2B2%28x%2B2%29=80\"$
\n" ); document.write( " $\"8x-20%2B2x%2B4=80\"$
\n" ); document.write( " $\"10x-16=80\"$
\n" ); document.write( " $\"10x=96\"$
\n" ); document.write( " $\"x=9.6\"$
\n" ); document.write( "So the original field was 9.6 in by 38.4 in.
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