Algebra.Com's Answer #131271 by MathLover1(20849)  You can put this solution on YOUR website! 1. Quadratic into Vertex Form\r \n" );
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document.write( " Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form | \n" );
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document.write( " Start with the given equation \n" );
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document.write( " Subtract from both sides \n" );
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document.write( " Factor out the leading coefficient  \n" );
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document.write( " Take half of the x coefficient to get (ie ). \n" );
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document.write( " Now square to get (ie ) \n" );
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document.write( " Now add and subtract this value inside the parenthesis. Doing both the addition and subtraction of does not change the equation \n" );
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document.write( " Now factor to get  \n" );
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document.write( " Distribute \n" );
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document.write( " Multiply \n" );
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document.write( " Now add to both sides to isolate y \n" );
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document.write( " Combine like terms \n" );
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document.write( " Now the quadratic is in vertex form where , , and . Remember (h,k) is the vertex and \"a\" is the stretch/compression factor. \n" );
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document.write( " Check: \n" );
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document.write( " Notice if we graph the original equation we get: \n" );
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document.write( " Graph of . Notice how the vertex is ( , ). \n" );
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document.write( " Notice if we graph the final equation we get: \n" );
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document.write( " Graph of . Notice how the vertex is also ( , ). \n" );
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document.write( " So if these two equations were graphed on the same coordinate plane, one would overlap another perfectly. So this visually verifies our answer. \n" );
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document.write( " Solved by pluggable solver: Min/Max of a Quadratic Function | \n" );
document.write( "The min/max of a quadratic equation is always at a point where its first differential is zero. This means that in our case, the value of at which the given equation has a maxima/minima must satisfy the following equation: \n" );
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document.write( " This point is a minima if value of coefficient of x2 is positive and vice versa. For our function the point x=0.5 is a The graph of the equation is : \n" );
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document.write( " Alternate method \n" );
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document.write( " In this method, we will use the perfect square method. \n" );
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document.write( " Step one: \n" );
document.write( " Make the coefficient of positive by multiplying it by in case . \n" );
document.write( " Maxima / Minima is decided from the sign of 'a'. \n" );
document.write( " If 'a' is positive then we have Minima and for 'a'negative we have Maxima. \n" );
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document.write( " Step two: \n" );
document.write( " Now make the perfect square with the same and coefficient. \n" );
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document.write( " Maxima / Minima lies at the point where this squared term is equal to zero. \n" );
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document.write( " Hence, \n" );
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document.write( " This point is a minima if value of coefficient of x2 is positive and vice versa. For our function the point x=0.5 is a . \n" );
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document.write( " For more on this topic, refer to Min/Max of a Quadratic equation. | \n" );
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