document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=176169>Question 176169</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534386172/algebrahomeworkh>college algebras</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> thanks in advance for your help.  How do I find the starting point of this line on a graph with this equation.  I am confused.  f(x)= - squareroot of (x+2) + 2\r<BR>\n" );
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document.write( "How do I put a neg. number under a square root?   Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #131251 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=131251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You don't put a negative under the square root.  The domain of this function is {x | x >= -2} for precisely that reason.  So start at -2 and get larger. </SPAN>\n" );
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