document.write( "Question 176137: sara drived off going west at a speed of 40 miles per hour.Now 2 hrs later, Jay decides to go after her and takes off at a speed of 90miles per hour. How long after Sara left will it be when Jay catches her?
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Algebra.Com's Answer #131228 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Sara drove off going west at a speed of 40 miles per hour. \n" ); document.write( "Now 2 hrs later, Jay decides to go after her and takes off at a speed of 90miles per hour. \n" ); document.write( "How long after Sara left will it be when Jay catches her? \n" ); document.write( "---------- \n" ); document.write( "Sara DATA: \n" ); document.write( "rate = 40 mph ; time = t hrs; distance = rt = 40t miles \n" ); document.write( "------------- \n" ); document.write( "Jay DATA: \n" ); document.write( "rate = 90 mph ; time = t-2; distance = rt = 90(t-2) \n" ); document.write( "------------- \n" ); document.write( "Equation: \n" ); document.write( "distance = distance \n" ); document.write( "40t = 90(t-2) \n" ); document.write( "40t = 90t - 180 \n" ); document.write( "50t = 180 \n" ); document.write( "t = 18/5 = 3.6 hrs. \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |