document.write( "Question 176130: PS is the hypotenuse of isosceles right triangle PST for P(-6,-2) and S(-6,5). Find some possible coordinates of T. \n" ); document.write( "
Algebra.Com's Answer #131222 by Edwin McCravy(20086)\"\" \"About 
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document.write( "For this line PS to be the hypotenuse of an isosceles\r\n" );
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document.write( "We could have two possibilities for such an\r\n" );
document.write( "isosceles right triangle. This is one \r\n" );
document.write( "possibility for T, call it little \"t\".\r\n" );
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document.write( "This is another possibility for T, we'll\r\n" );
document.write( "call it big T.\r\n" );
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document.write( "Put them together side by side and you have\r\n" );
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document.write( "Now from P to S is 7 units. That means that the diagonal of \r\n" );
document.write( "the square is 7 units long.  We also know that both diagonals\r\n" );
document.write( "have the same length, so let's draw in the other diagonal Tt,\r\n" );
document.write( "from the T on the left to the t on the right, crossing the other\r\n" );
document.write( "diagonal PS at their common midpoint X: \r\n" );
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document.write( "Tt has to also be 7 units long. because PS is.\r\n" );
document.write( "That makes Xt be half of that or 3.5 units long.\r\n" );
document.write( "Now X is 6 units horizontally away from the y-axis\r\n" );
document.write( "and since Xt = 3.5 units, t has to be 6-3.5 or 2.5\r\n" );
document.write( "units from the y-axis.  That means the x-coordinate \r\n" );
document.write( "of t has to be -2.5.  \r\n" );
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document.write( "We know what the y-coordinate of t is because it's \r\n" );
document.write( "the same as the y-coordinate of X.  That's the \r\n" );
document.write( "midpoint of P(-6,-2) and P(-6,5), or X(-6,1.5), and \r\n" );
document.write( "so t is the point t(-2.5,1.5).\r\n" );
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document.write( "Use the same reasoning and you'll get that the \r\n" );
document.write( "coordinates of T are T(-9.5,1.5)\r\n" );
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document.write( "Edwin
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