document.write( "Question 24635: how do i do this problem?\r
\n" ); document.write( "\n" ); document.write( "Solve by graphing\r
\n" ); document.write( "\n" ); document.write( "{x+7=y
\n" ); document.write( "{-4+2=y
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Algebra.Com's Answer #13119 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming that you probably meant to write:
\n" ); document.write( "y = x+7
\n" ); document.write( "y = -4x + 2\r
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\n" ); document.write( "\n" ); document.write( "To solve by graphing, just draw the graphs and see where the two lines cross. If you need additional help obtaining the graphs of these lines, I wrote three lesson plans for algebra.com on graphing a straight line. These are both in slope intercept form so graphing the lines should be easy. \r
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\n" ); document.write( "\n" ); document.write( "The first line has a y intercept of 7 and a slope of \"%28rise%29%2F%28run%29+=+1%2F1\".
\n" ); document.write( "The second line has a y intercept of 2, and a slope of \"%28rise%29%2Frun%29+=+%28-4%29%2F1\". They should look like this, \r
\n" ); document.write( "\n" ); document.write( "\"graph%28400%2C400%2C+-10%2C10%2C-10%2C10%2C+x%2B7+%2C+-4x+%2B2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Notice that the lines cross at a point where x = -1, and y =6. Therefore, the solution is the point (-1,6).\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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