document.write( "Question 176031: In the following addition problem, Y, O, and U are different digits. Solve the following problem:\r
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Algebra.Com's Answer #131170 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "In the following addition problem, Y, O, and U are different digits. Solve the following problem:
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document.write( "I'm going to change the letter \"O\" to the letter \"Q\" \r\n" );
document.write( "because the letter \"O\" looks too much like zero.\r\n" );
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document.write( "YOU + YOU + YOU = UUU\r\n" );
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document.write( "Sorry there can't be a solution. Why?\r\n" );
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document.write( " Y Q U\r\n" );
document.write( " Y Q U\r\n" );
document.write( " Y Q U\r\n" );
document.write( " -----\r\n" );
document.write( " U U U\r\n" );
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document.write( "Adding the rightmost column\r\n" );
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document.write( "U + U + U\r\n" );
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document.write( "If there was 0 (nothing) to carry, then\r\n" );
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document.write( "U + U + U = U\r\n" );
document.write( "       3U = U\r\n" );
document.write( "       2U = 0\r\n" );
document.write( "        U = 0\r\n" );
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document.write( "If U were 0, then the next column would be\r\n" );
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document.write( "Q+Q+Q = 0 or Q+Q+Q = 10\r\n" );
document.write( "   3Q = 0       3Q = 10\r\n" );
document.write( "    Q = 0        Q = \"3%261%2F3\"  \r\n" );
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document.write( "But Q can't be 0 because U = 0, and it can't be\r\n" );
document.write( "\"3%261%2F3\" so there had to be 1 to carry.  \r\n" );
document.write( "Therefore\r\n" );
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document.write( "U + U + U = 10 + U\r\n" );
document.write( "       3U = 10\r\n" );
document.write( "        U = 5\r\n" );
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document.write( "So therefore we have:\r\n" );
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document.write( "   1\r\n" );
document.write( " Y Q 5\r\n" );
document.write( " Y Q 5\r\n" );
document.write( " Y Q 5\r\n" );
document.write( " -----\r\n" );
document.write( " 5 5 5\r\n" );
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document.write( "Adding up the middle column with the carry,\r\n" );
document.write( "we have\r\n" );
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document.write( "1 + Q + Q + Q = 5 or 15\r\n" );
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document.write( "1 + 3Q = 5   or   1 + 3Q = 15 \r\n" );
document.write( "    3Q = 4   or       3Q = 14\r\n" );
document.write( "     Q = \"3%2F4\"     Q = \"4%262%2F3\"\r\n" );
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document.write( "But Q can't be a fraction, so there\r\n" );
document.write( "can be no solution.  Sorry.\r\n" );
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document.write( "Edwin
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