document.write( "Question 176031: In the following addition problem, Y, O, and U are different digits. Solve the following problem:\r
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document.write( "YOU + YOU + YOU = UUU \n" );
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Algebra.Com's Answer #131157 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! First of all, Y cannot be \n" ); document.write( "a leading digit, and U cannot be \n" ); document.write( "That would make the sum \n" ); document.write( "------- \n" ); document.write( "So, Y and U must be one of the digits 1-9 \n" ); document.write( "Also, UUU must be less than \n" ); document.write( "more would be 4 digits, not 3. \n" ); document.write( "If UUU is less than \n" ); document.write( "3 x YOU must be less than \n" ); document.write( " \n" ); document.write( "------- \n" ); document.write( "When I add up the units column which is U + U + U, \n" ); document.write( "I still get U in the sum, UUU, but I must have a \n" ); document.write( "carry which would be \n" ); document.write( " \n" ); document.write( "First I'll say the carry is \n" ); document.write( "U + U + U = U + 10 \n" ); document.write( "3U = U + 10 \n" ); document.write( "2U = 10 \n" ); document.write( "U = 5 and \n" ); document.write( "UUU = 555 \n" ); document.write( "Now I'll say the carry is \n" ); document.write( "U + U + U = U + 20 \n" ); document.write( "3U = U + 20 \n" ); document.write( "2U = 20 \n" ); document.write( "U = 10 \n" ); document.write( "This is 2 digits, and it needs to be 1 \n" ); document.write( "Also, any higher carrys, \n" ); document.write( "would also be 2 digits \n" ); document.write( "So, U = 5 and the carry is \n" ); document.write( "I have 3 x YO5 = 555 \n" ); document.write( "I'll divide both sides by 3 \n" ); document.write( "YO5 = 555/3 \n" ); document.write( "YOU = 185 \n" ); document.write( "185 + 185 + 185 = 555 answer \n" ); document.write( " |