document.write( "Question 176031: In the following addition problem, Y, O, and U are different digits. Solve the following problem:\r
\n" ); document.write( "\n" ); document.write( "YOU + YOU + YOU = UUU
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Algebra.Com's Answer #131157 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
First of all, Y cannot be \"0\" because it is
\n" ); document.write( "a leading digit, and U cannot be \"0\" because
\n" ); document.write( "That would make the sum \"000\", which it can't be
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\n" ); document.write( "So, Y and U must be one of the digits 1-9
\n" ); document.write( "Also, UUU must be less than \"999\" since one
\n" ); document.write( "more would be 4 digits, not 3.
\n" ); document.write( "If UUU is less than \"999\", that means
\n" ); document.write( "3 x YOU must be less than \"333\". It can't be
\n" ); document.write( "\"333\", because each digit must be different
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\n" ); document.write( "When I add up the units column which is U + U + U,
\n" ); document.write( "I still get U in the sum, UUU, but I must have a
\n" ); document.write( "carry which would be \"10\", \"20\",\"30\",
\n" ); document.write( "\"40\" up to \"90\".
\n" ); document.write( "First I'll say the carry is \"10\"
\n" ); document.write( "U + U + U = U + 10
\n" ); document.write( "3U = U + 10
\n" ); document.write( "2U = 10
\n" ); document.write( "U = 5 and
\n" ); document.write( "UUU = 555
\n" ); document.write( "Now I'll say the carry is \"20\"
\n" ); document.write( "U + U + U = U + 20
\n" ); document.write( "3U = U + 20
\n" ); document.write( "2U = 20
\n" ); document.write( "U = 10
\n" ); document.write( "This is 2 digits, and it needs to be 1
\n" ); document.write( "Also, any higher carrys, \"30\",\"40\", etc
\n" ); document.write( "would also be 2 digits
\n" ); document.write( "So, U = 5 and the carry is \"10\"
\n" ); document.write( "I have 3 x YO5 = 555
\n" ); document.write( "I'll divide both sides by 3
\n" ); document.write( "YO5 = 555/3
\n" ); document.write( "YOU = 185
\n" ); document.write( "185 + 185 + 185 = 555 answer
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