document.write( "Question 176000: A motorboat travels 147km in 3 hours going upstream and 546km in 6 hours going downstream. What is the speed of the boat in still water, and what is the speed of the current?
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Algebra.Com's Answer #131154 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A motorboat travels 147km in 3 hours going upstream and 546km in 6 hours going downstream. What is the speed of the boat in still water, and what is the speed of the current? \n" ); document.write( ": \n" ); document.write( "Let x = boat speed in still water \n" ); document.write( "Let y = speed of the current \n" ); document.write( ": \n" ); document.write( "Write two distance equations, one for upstream and one for downstream \n" ); document.write( "dist = time * speed \n" ); document.write( "3x - 3y = 147 \n" ); document.write( "and \n" ); document.write( "6x + 6y = 546 \n" ); document.write( "simplify, divide equation by 2 \n" ); document.write( "3x + 3y = 273 \n" ); document.write( ": \n" ); document.write( "Add these two equations \n" ); document.write( "3x - 3y = 147 \n" ); document.write( "3x + 3y = 273 \n" ); document.write( "-----------------addition eliminates y, find x \n" ); document.write( "6x = 420 \n" ); document.write( "x = \n" ); document.write( "x = 70 km/hr in still water \n" ); document.write( ": \n" ); document.write( "Find the current using the upstream equation \n" ); document.write( "3(70) - 3y = 147 \n" ); document.write( "210 - 3y = 147 \n" ); document.write( "-3y = 147 + 210 \n" ); document.write( "-3y = -63 \n" ); document.write( "y = \n" ); document.write( "y = +21 km/hr is the current \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the down stream equation \n" ); document.write( "6(70 + 21) = \n" ); document.write( "6 * 91 = 546, confirms our solutions\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |