document.write( "Question 24619: Find the solution to the system y=xsquared+5 and y=2x+4
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Algebra.Com's Answer #13114 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
\"y=x%5E2+%2B+5\"
\n" ); document.write( "\"y+=+2x+%2B+4\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore
\n" ); document.write( "y=y
\n" ); document.write( "\"x%5E2+%2B5+=+2x+%2B+4\", which is a quadratic equation. Solve by setting it equal to zero:
\n" ); document.write( "\"x%5E2+%2B+5+-+2x+-+4=+0\"
\n" ); document.write( "\"x%5E2+-2x+%2B+1+=+0\"
\n" ); document.write( "\"%28x-1%29%5E2+=+0\"
\n" ); document.write( "\"x=1\"\r
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\n" ); document.write( "\n" ); document.write( "Substitute back into either equation, usually the simplest one is best!
\n" ); document.write( "y = 2x +4
\n" ); document.write( "y = 2(1) + 4
\n" ); document.write( "y = 6\r
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\n" ); document.write( "\n" ); document.write( "There is only one point of intersection, (1, 6) .\r
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\n" ); document.write( "\n" ); document.write( "Just for fun, let's check by graphing:
\n" ); document.write( "\"graph+%28400%2C400%2C+-10%2C10%2C-10%2C10%2C+x%5E2%2B5%2C+2x%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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