document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3082>Question 3082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 24 feet less than its length.  What polynomials will represent its perimeter and area if the actual length is 44 feet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1311 by </B><A HREF=/tutors/aboutme.mpl?userid=thechamp1011><B>thechamp1011(19)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=thechamp1011><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> TO FIND THE PERIMETER: DRAW A RECTANGLE FIRST, SINCE YOU HAVE 2 SIDES OF LENGTH AND 2 SIDES OF WIDTH. \r<BR>\n" );
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document.write( "THE PERIMETER FORMULA FOR RECTANGLE IS: P=2L+2w\r<BR>\n" );
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document.write( "SINCE WE KNOW THE THE WIDTH OF THE RECTALGLE WHICH IS 24 LESS THAN THE LENGHT, WE CAN WRITE THE WIDTH EXPRESSION AS: W=L-24\r<BR>\n" );
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document.write( "NOW SUBSTITUTE THE WIDTH EQUATION TO THE PERIMETER FORMULA TO FIND THE PERIMETER OF THE POLYNOMIALS: P=2L+2W<BR>\n" );
document.write( "                 P=2L+(L-24)<BR>\n" );
document.write( "                 P=3L-24\r<BR>\n" );
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document.write( "THE AREA OF THE RECTANGLE IS : A=L(W)<BR>\n" );
document.write( "                               A=44(44-24)=44(20)<BR>\n" );
document.write( "                                         A=880FEET </SPAN>\n" );
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