document.write( "Question 175973: I have a question over a worksheet I was given, my dad and I are stuck on how to set it up. It is over using the system of linear equations to find the present age.\r
\n" ); document.write( "\n" ); document.write( "QUESTION: In 1987, Joy was 3 times as old as Ali. If Ali was born 8 years after Joy, what age will each be in 1999?\r
\n" ); document.write( "\n" ); document.write( "Please help. Thank You.
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Algebra.Com's Answer #131093 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I'll reference their ages to 1999, and I'll say that at that year
\n" ); document.write( "\"j\"= Joy's age
\n" ); document.write( "\"a\"= Ali's age
\n" ); document.write( "Given:
\n" ); document.write( "In 1987, Joy's age was
\n" ); document.write( "\"j+-+%281999+-+1987%29\"
\n" ); document.write( "\"j+-+12\"
\n" ); document.write( "In 1987, Ali's age was
\n" ); document.write( "\"a+-+12\"
\n" ); document.write( "(1) \"j+-+12+=+3%28a+-+12%29\"
\n" ); document.write( "The difference in their ages is 8 years and Ali is the younger, so
\n" ); document.write( "(2) \"a+=+j+-+8\"
\n" ); document.write( "Substitute (2) in (1)
\n" ); document.write( "\"j+-+12+=+3%2A%28j+-+8+-+12%29\"
\n" ); document.write( "\"j+-+12+=+3%2A%28j+-+20%29\"
\n" ); document.write( "\"j+-+12+=+3j+-+60\"
\n" ); document.write( "\"2j+=+48\"
\n" ); document.write( "\"j+=+24\"
\n" ); document.write( "And, since
\n" ); document.write( "\"a+=+j+-+8\"
\n" ); document.write( "\"a+=+24+-+8\"
\n" ); document.write( "\"a+=+16\"
\n" ); document.write( "Joy is 24 and Ali is 16 in 1999
\n" ); document.write( "check:
\n" ); document.write( "(1) \"j+-+12+=+3%28a+-+12%29\"
\n" ); document.write( "(1) \"24+-+12+=+3%2816+-+12%29\"
\n" ); document.write( "\"12+=+3%2A4\"
\n" ); document.write( "\"12+=+12\"
\n" ); document.write( "OK
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