document.write( "Question 175893: Demand equation. Helen’s Health Foods usually sells
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document.write( "400 cans of ProPac Muscle Punch per week when the price
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document.write( "is $5 per can. After experimenting with prices for some
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document.write( "time, Helen has determined that the weekly demand can
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document.write( "be found by using the equation
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document.write( "d = 600 - 40p,
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document.write( "where d is the number of cans and p is the price per can.
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document.write( "a) Will Helen sell more or less Muscle Punch if she raises
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document.write( "her price from $5?
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document.write( "b) What happens to her sales every time she raises her
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document.write( "price by $1?
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document.write( "c) Graph the equation.
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document.write( "d) What is the maximum price that she can charge and
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document.write( "still sell at least one can? \n" );
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Algebra.Com's Answer #131091 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Demand equation. Helen’s Health Foods usually sells \n" ); document.write( "400 cans of ProPac Muscle Punch per week when the price \n" ); document.write( "is $5 per can. After experimenting with prices for some \n" ); document.write( "time, Helen has determined that the weekly demand can \n" ); document.write( "be found by using the equation \n" ); document.write( "d = 600 - 40p, \n" ); document.write( "where d is the number of cans and p is the price per can. \n" ); document.write( ": \n" ); document.write( "a) Will Helen sell more or less Muscle Punch if she raises \n" ); document.write( "her price from $5? \n" ); document.write( "Less, 40p is subtracted from 600 \n" ); document.write( ": \n" ); document.write( "b) What happens to her sales every time she raises her \n" ); document.write( "price by $1? \n" ); document.write( "She sells 40 less cans \n" ); document.write( ": \n" ); document.write( "c) Graph the equation. \n" ); document.write( "graph y = 600 - 40x \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "d) What is the maximum price that she can charge and \n" ); document.write( "still sell at least one can? \n" ); document.write( "Find p when d = 1 \n" ); document.write( "600 - 40p = 1 \n" ); document.write( "-40p = 1 -600 \n" ); document.write( "p = \n" ); document.write( "p = +14.975 \n" ); document.write( "We can say that if she sells it for $14.97, she will still sell at least one can \n" ); document.write( "Check this: d = 600 - 40(14.97) \n" ); document.write( "d = 600 - 598.8 \n" ); document.write( "d ~ 1 can \n" ); document.write( " |