document.write( "Question 175921: Solve each system by the addition method.\r
\n" ); document.write( "\n" ); document.write( "3/7x+5/9y=27
\n" ); document.write( "1/9x+2/7y=7\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "3x-2.5y=7.125
\n" ); document.write( "2.5x-3y=7.3125
\n" ); document.write( "

Algebra.Com's Answer #131084 by Alan3354(69443)\"\" \"About 
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Solve each system by the addition method.
\n" ); document.write( "3/7x+5/9y=27
\n" ); document.write( "1/9x+2/7y=7
\n" ); document.write( "Since it says \"linear systems\" I'll assume 3/7x means (3/7)x
\n" ); document.write( "(3x/7) + (5y/9) = 27 Do them like this to avoid ambiguities.
\n" ); document.write( "(x/9) + (2y/7) = 7
\n" ); document.write( "Multiply both eqns by 63 to eliminate fractions.
\n" ); document.write( "27x + 35y = 1701
\n" ); document.write( "7x + 18y = 441
\n" ); document.write( "Multiply the 1st eqn by 7 and the 2nd by 27 to get 189x in both
\n" ); document.write( "189x + 245y = 11907
\n" ); document.write( "189x + 486y = 11907
\n" ); document.write( "Subtract eqn 2 from eqn 1
\n" ); document.write( "0x - 241y = 0
\n" ); document.write( "y = 0
\n" ); document.write( "x = 11907/189
\n" ); document.write( "x = 63
\n" ); document.write( "-------------
\n" ); document.write( "and
\n" ); document.write( "3x-2.5y=7.125
\n" ); document.write( "2.5x-3y=7.3125
\n" ); document.write( "--------------
\n" ); document.write( "Multiply both by 16
\n" ); document.write( "48x - 40y = 114
\n" ); document.write( "40x - 48y = 117
\n" ); document.write( "All integers now
\n" ); document.write( "Multiply the 1st eqn by 5, the 2nd by 6
\n" ); document.write( "240x - 200y = 570
\n" ); document.write( "240x - 288y = 702
\n" ); document.write( "Subtract the 2nd from the 1st
\n" ); document.write( "0x + 88y = -132
\n" ); document.write( "y = -1.5
\n" ); document.write( "-------------
\n" ); document.write( "Sub for y into 2.5x-3y=7.3125
\n" ); document.write( "2.5x -3*(-1.5) = 7.3125
\n" ); document.write( "2.5x + 4.5 = 7.3125
\n" ); document.write( "2.5x = 2.8125
\n" ); document.write( "x = 1.125\r
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