document.write( "Question 175921: Solve each system by the addition method.\r
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document.write( "3/7x+5/9y=27
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document.write( "1/9x+2/7y=7\r
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document.write( "and\r
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document.write( "3x-2.5y=7.125
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document.write( "2.5x-3y=7.3125 \n" );
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Algebra.Com's Answer #131084 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve each system by the addition method. \n" ); document.write( "3/7x+5/9y=27 \n" ); document.write( "1/9x+2/7y=7 \n" ); document.write( "Since it says \"linear systems\" I'll assume 3/7x means (3/7)x \n" ); document.write( "(3x/7) + (5y/9) = 27 Do them like this to avoid ambiguities. \n" ); document.write( "(x/9) + (2y/7) = 7 \n" ); document.write( "Multiply both eqns by 63 to eliminate fractions. \n" ); document.write( "27x + 35y = 1701 \n" ); document.write( "7x + 18y = 441 \n" ); document.write( "Multiply the 1st eqn by 7 and the 2nd by 27 to get 189x in both \n" ); document.write( "189x + 245y = 11907 \n" ); document.write( "189x + 486y = 11907 \n" ); document.write( "Subtract eqn 2 from eqn 1 \n" ); document.write( "0x - 241y = 0 \n" ); document.write( "y = 0 \n" ); document.write( "x = 11907/189 \n" ); document.write( "x = 63 \n" ); document.write( "------------- \n" ); document.write( "and \n" ); document.write( "3x-2.5y=7.125 \n" ); document.write( "2.5x-3y=7.3125 \n" ); document.write( "-------------- \n" ); document.write( "Multiply both by 16 \n" ); document.write( "48x - 40y = 114 \n" ); document.write( "40x - 48y = 117 \n" ); document.write( "All integers now \n" ); document.write( "Multiply the 1st eqn by 5, the 2nd by 6 \n" ); document.write( "240x - 200y = 570 \n" ); document.write( "240x - 288y = 702 \n" ); document.write( "Subtract the 2nd from the 1st \n" ); document.write( "0x + 88y = -132 \n" ); document.write( "y = -1.5 \n" ); document.write( "------------- \n" ); document.write( "Sub for y into 2.5x-3y=7.3125 \n" ); document.write( "2.5x -3*(-1.5) = 7.3125 \n" ); document.write( "2.5x + 4.5 = 7.3125 \n" ); document.write( "2.5x = 2.8125 \n" ); document.write( "x = 1.125\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |