document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=24625>Question 24625</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have homework but i can't figure it out. please help i'll give you the problem to see if you can figure it out. i have the answer just not the actual work. please help. here it is.  \r<BR>\n" );
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document.write( "2y + 7 = y<BR>\n" );
document.write( "the answer is y = -7 but i can't get how to get to the answer Help!it seems so simple but i just can't get it\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #13107 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=13107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2y + 7 = y<BR>\n" );
document.write( "Subtract \"y\" from both sides of the equation, as follows:<BR>\n" );
document.write( "2y + 7 -y = y-y<BR>\n" );
document.write( "Then simplify both sides to get:<BR>\n" );
document.write( " y+7 = 0<BR>\n" );
document.write( "Now, subtract \"7\" from both sides to get:<BR>\n" );
document.write( " y+7-7 = 0-7<BR>\n" );
document.write( " y  = -7\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.  </SPAN>\n" );
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