document.write( "Question 175949: A boat travels at the rate of 8 kph in still water. If it can travel a given distance upstream in 5 hours and the same distance downstream in 3 hours, what is the rate of the current? \n" ); document.write( "
Algebra.Com's Answer #131057 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Distance= Rate * Time
\n" ); document.write( "The distance going both directions is the same.
\n" ); document.write( "Let c be the speed of the current
\n" ); document.write( "\"DistanceUpstream+=+%288+-+c%29%2A5\" = \"40+-+5c\"
\n" ); document.write( "\"DistanceDownStream+=+%288+%2B+c%29%2A3\" = \"24+%2B+3c\"
\n" ); document.write( "So
\n" ); document.write( "\"40-5c+=+24+%2B+3c\"
\n" ); document.write( "\"16+=+8c\"
\n" ); document.write( "\"2+=+c\"
\n" ); document.write( "The current is 2 kph\r
\n" ); document.write( "\n" ); document.write( "So how far did the boat travel each way?
\n" ); document.write( "(8-2)* 5 = 30k
\n" ); document.write( "(8+2)* 3 = 30K
\n" ); document.write( "
\n" );