document.write( "Question 24591: Randy is building a fence at the side of his warehouse. He has 120 m of fencing and plans to use the side of the warehouse as one side of the rectangular fenced area. What are the dimensions of the maximum area Randy can enclose?\r
\n" ); document.write( "\n" ); document.write( "* I REALLY NEED HELP WITH THIS>.its due tomorrow
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Algebra.Com's Answer #13104 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Is this for a calculus class?
\n" ); document.write( "You don't need calculus to solve it anyway
\n" ); document.write( "Always draw a picture\r
\n" ); document.write( "\n" ); document.write( "|------------------|
\n" ); document.write( "|wwwwwwwwarew|
\n" ); document.write( "|wwwwwwhouseww|
\n" ); document.write( "|------------------|
\n" ); document.write( "|aaaafencedaaaaaa|
\n" ); document.write( "|------------------|\r
\n" ); document.write( "\n" ); document.write( "call the sides of the fenced area x. both sides are equal in a rectangle
\n" ); document.write( "the sum of the 2 sides is 2x
\n" ); document.write( "if there are 120m of fencing, the third side is 120 - 2x
\n" ); document.write( "so the equation for area is
\n" ); document.write( "\"A+=+x%2A%28120+-+2%2Ax%29\"
\n" ); document.write( "expanding
\n" ); document.write( "\"A+=+120+%2A+x+-+2%2Ax%5E2\"
\n" ); document.write( "try plugging in values for x to see what A is
\n" ); document.write( "x = 10
\n" ); document.write( "\"A+=+120+%2A+10+-+2+%2A+%2810%5E2%29\"
\n" ); document.write( "A = 1000
\n" ); document.write( "x = 20
\n" ); document.write( "\"A+=+120+%2A+20+-+2+%2A+%2820%5E2%29\"
\n" ); document.write( "A = 1600
\n" ); document.write( "x = 40
\n" ); document.write( "\"A+=+120+%2A+40+-+2+%2A+%2840%5E2%29\"
\n" ); document.write( "A = 1600
\n" ); document.write( "I get the same answer for x = 20 and x = 40, so the max must be in between,
\n" ); document.write( "since the curve is a parabola
\n" ); document.write( "x = 30
\n" ); document.write( "\"A+=+120+%2A+30+-+2+%2A+%2830%5E2%29\"
\n" ); document.write( "A = 1800
\n" ); document.write( "that is the max area in square meters, so the sides are 30 m and the third side
\n" ); document.write( "is 120 - 2(30) = 60 meters
\n" ); document.write( "check: 30 * 60 = 1800 m^2 for the area
\n" ); document.write( "and 2 * 30 + 60 = 120 for the length
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