document.write( "Question 175829: C/D or C over D + 2
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document.write( "C/D+2 = ???\r
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document.write( "Answers are C+2D over D or C+2D\r
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document.write( "Also what are the possible values of x such that 3(xsquared) - 2x =0
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document.write( "three x squared minus two x =0\r
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document.write( "-2/3 or 0 or 2/3 or 0 and 2/3\r
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document.write( "finally, \r
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document.write( "sqrt 3 + sqrt 27 = ?????\r
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Algebra.Com's Answer #130988 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (C/D)+2 = ??? \n" ); document.write( "Answers are C+2D over D or C+2D \n" ); document.write( "least common denominator is \"D\": \n" ); document.write( "= (C/D) + (2D/D)\r \n" ); document.write( "\n" ); document.write( "= (c+2D)/D \n" ); document.write( "--------------------------------- \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also what are the possible values of x such that 3(x^2) - 2x =0 \n" ); document.write( "Factor to get: \n" ); document.write( "x(3x-2) = 0 \n" ); document.write( "Since the product is zero, one of the factors must be zero: \n" ); document.write( "x = 0 or 3x-2 = 0 \n" ); document.write( "x = 0 or x = 2/3 \n" ); document.write( "------------------------ \n" ); document.write( "finally, \n" ); document.write( "sqrt 3 + sqrt 27 = ????? \n" ); document.write( "= sqrt(3) + sqrt(9*3) \n" ); document.write( "= sqrt(3) + sqrt(9)*sqrt(3) \n" ); document.write( "= sqrt(3) + 3*sqrt(3) \n" ); document.write( "= 4sqrt(3) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |