document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175821>Question 175821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "use the sum and differences formulas to find the exact value of tan75 degrees<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130933 by </B><A HREF=/tutors/aboutme.mpl?userid=srcedwards><B>srcedwards(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=srcedwards><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130933\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> tan 75 = tan (45 + 30).  tan (a + b) = (tan a + tan b)/(1 - tan a * tan b).  So your problem, tan 75 = tan (45 + 30) = (tan 45 + tan 30)/(1 - tan 45 * tan 30).\r<BR>\n" );
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document.write( "45 and 30 are special angles, so you should know them; tan 30 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >/3 and tan 45 = 1.  Just plug these in and solve! </SPAN>\n" );
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