document.write( "Question 175811: The sum of two numbers is 133. Four times the smaller of the two numbers equals three times the greater number. Find the numbers. \n" ); document.write( "
Algebra.Com's Answer #130916 by jojo14344(1513)\"\" \"About 
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\n" ); document.write( "Remember----->\"system%28x=SmallerNumber%2Cy=GreaterNumber%29\"}
\n" ); document.write( "1st Condition:
\n" ); document.write( "\"x%2By=133\"
\n" ); document.write( "2nd condition:
\n" ); document.write( "\"4x=3y\"-----> we get: \"cross%284%29x%2Fcross%284%29=%283y%29%2F4\"
\n" ); document.write( "\"x=%283%2F4%29y\", condition 3 & subst in condition 1:
\n" ); document.write( ".
\n" ); document.write( "\"%283%2F4%29y%2By=133\"
\n" ); document.write( "\"%283y%2B4y%29%2F4=133\", cross multiply
\n" ); document.write( "\"7y=133%2A4=532\"
\n" ); document.write( "\"cross%287%29y%2Fcross%287%29=cross%28532%2976%2Fcross%287%29\"
\n" ); document.write( "\"highlight%28y=76%29\", Greater Number
\n" ); document.write( "Go back condition 3:
\n" ); document.write( "\"x=%283%2F4%29%2876%29=228%2F4\"
\n" ); document.write( "\"highlight%28x=57%29\", Smaller Number
\n" ); document.write( "In doubt? Check via condition 2:
\n" ); document.write( "\"4%2A57=3%2A76\"
\n" ); document.write( "\"228=228\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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