document.write( "Question 175719: 8X^3y^6+27 \n" ); document.write( "
Algebra.Com's Answer #130911 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
I'm assuming you're asked to factor the expression.
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\n" ); document.write( "Starting with:
\n" ); document.write( "8X^3y^6+27
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\n" ); document.write( "Notice, I can rewrite the above as:
\n" ); document.write( "(2xy^2)^3+(3)^3
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\n" ); document.write( "Now, it is a \"sum of cubes\" -- a special factor... where:
\n" ); document.write( "a^3 + b^3 = (a + b)(a^2 – ab + b^2)
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\n" ); document.write( "In your case,
\n" ); document.write( "a = 2xy^2
\n" ); document.write( "b = 3
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\n" ); document.write( "Plugging the above into:
\n" ); document.write( "a^3 + b^3 = (a + b)(a^2 – ab + b^2)
\n" ); document.write( "we get:
\n" ); document.write( "(2xy^2)^3 + 3^3 = (2xy^2 + 3)((2xy^2)^2 – 3(2xy^2) + 3^2)
\n" ); document.write( "(2xy^2)^3 + 3^3 = (2xy^2 + 3)(4x^2y^4 – 6xy^2 + 9)
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