document.write( "Question 172128: Graph and give the coordinates of the vertex,x and y intercepts, and graph\r
\n" ); document.write( "\n" ); document.write( "\"y=f%28x%29=-x%5E2-6x\"
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Algebra.Com's Answer #130897 by EMStelley(208)\"\" \"About 
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In order to find the vertex (h,k), the easiest way is to use the formula
\n" ); document.write( "\"h=-b%2F%282a%29\"
\n" ); document.write( "So here, a=-1, b=-6, and c=0, so
\n" ); document.write( "\"h=-%28-6%29%2F%282%28-1%29%29=6%2F%28-2%29=-3\"
\n" ); document.write( "To find k, you just evaluate the function at x=-3. So
\n" ); document.write( "\"f%28-3%29=-%28%28-3%29%5E2%29-6%28-3%29=-9%2B18=9\"
\n" ); document.write( "So the vertex is (-3,9). The y intercept is found by setting x equal to 0.
\n" ); document.write( "\"f%280%29=-0%5E2-6%280%29=0\"
\n" ); document.write( "So the y intercept is the origin, (0,0).
\n" ); document.write( "The x intercepts are found by setting y = 0.
\n" ); document.write( "\"0=-x%5E2-6x\"
\n" ); document.write( "Factoring, we get
\n" ); document.write( "\"0=x%28-x-6%29\"
\n" ); document.write( "So
\n" ); document.write( "\"x=0\" and \"-x-6=0\"
\n" ); document.write( "So our two x intercepts are at x=0 and x=-6.
\n" ); document.write( "Finally, graphing, we get
\n" ); document.write( "\"graph%28300%2C200%2C+-10%2C10%2C-10%2C10%2C-x%5E2-6x%29\"
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