document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=175758>Question 175758</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An artist wants her painting to be in the shape of a golden rectangle. If the length of the painting is 36 inches, then what should be the width?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #130893 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=130893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the width (shorter length) of a golden rectangle is 1, then the length is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281+%2B+sqrt%285%29%29%2F2 ALIGN=MIDDLE  ALT=\"%281+%2B+sqrt%285%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  So for this situation, if the width is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x ALIGN=MIDDLE  ALT=\"x\"   DISABLED_style= \"max-width:90%; height:auto;\" > and 36 is the length,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x+%281+%2B+sqrt%285%29%29%29%2F2+=+36 ALIGN=MIDDLE  ALT=\"%28x+%281+%2B+sqrt%285%29%29%29%2F2+=+36\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Solve for x:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%2836+%2A+2%29%2F%281+%2B+sqrt%285%29%29+=+72%2F%281+%2B+sqrt%285%29%29 ALIGN=MIDDLE  ALT=\"x+=+%2836+%2A+2%29%2F%281+%2B+sqrt%285%29%29+=+72%2F%281+%2B+sqrt%285%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now rationalize the denominator using the conjugate of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281+%2B+sqrt%285%29%29 ALIGN=MIDDLE  ALT=\"%281+%2B+sqrt%285%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, namely <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1+-+sqrt%285%29%29 ALIGN=MIDDLE  ALT=\"1+-+sqrt%285%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2872%2F%281+%2B+sqrt%285%29%29%29%28%281+-+sqrt%285%29%29%2F%281+-+sqrt%285%29%29%29=%2872+-+72%28sqrt%285%29%29%29%2F%28-4%29=18%2Asqrt%285%29+-+18 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "That's the exact answer.  If you need a numerical approximation, use your calculator.  However, round your answer to the nearest inch because you should never, unless specifically instructed otherwise, express an answer to a calculation involving measurements to a greater precision than the least precise given measurement.  In this case, the length was expressed to the inch, so your answer must be to the nearest inch. </SPAN>\n" );
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