document.write( "Question 175786: Evalute expression:\r
\n" ); document.write( "\n" ); document.write( "3x-4y+9 when x=2 and y=5
\n" ); document.write( "

Algebra.Com's Answer #130874 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
Evalute expression:
\n" ); document.write( "3x - 4y + 9 when x=2 and y=5
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "         3x - 4y + 9\r\n" );
document.write( "\r\n" );
document.write( "Take out the x and put (2) in its place\r\n" );
document.write( "Take out the y and put (5) in its place:\r\n" );
document.write( "Then you have:\r\n" );
document.write( "\r\n" );
document.write( "        3(2) - 4(5) + 9\r\n" );
document.write( "\r\n" );
document.write( "Now we must do multiplications before additions\r\n" );
document.write( "and subtractions, so take out the 3(2) and put\r\n" );
document.write( "6 (which is 3 times 2) in its place.\r\n" );
document.write( "\r\n" );
document.write( "Also take out the 4(5) and put 20 (which is 4\r\n" );
document.write( "times 5) in its place. Then we have:\r\n" );
document.write( "\r\n" );
document.write( "           6 - 20 + 9\r\n" );
document.write( "\r\n" );
document.write( "Now there is only a subtraction and an addition\r\n" );
document.write( "left to do, so we must do them in the order of\r\n" );
document.write( "left to right.  We come to 6 - 20 first, so we \r\n" );
document.write( "do that and get -14.  Then we replace 6 - 20 by\r\n" );
document.write( "-14.  Then we have\r\n" );
document.write( "\r\n" );
document.write( "             -14 + 9\r\n" );
document.write( "\r\n" );
document.write( "Now we do that addition and end up with -5.\r\n" );
document.write( "\r\n" );
document.write( "So the answer is -5.\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" ); document.write( "
\n" );