document.write( "Question 175786: Evalute expression:\r
\n" );
document.write( "\n" );
document.write( "3x-4y+9 when x=2 and y=5 \n" );
document.write( "
Algebra.Com's Answer #130874 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! Evalute expression: \n" ); document.write( "3x - 4y + 9 when x=2 and y=5 \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( " 3x - 4y + 9\r\n" ); document.write( "\r\n" ); document.write( "Take out the x and put (2) in its place\r\n" ); document.write( "Take out the y and put (5) in its place:\r\n" ); document.write( "Then you have:\r\n" ); document.write( "\r\n" ); document.write( " 3(2) - 4(5) + 9\r\n" ); document.write( "\r\n" ); document.write( "Now we must do multiplications before additions\r\n" ); document.write( "and subtractions, so take out the 3(2) and put\r\n" ); document.write( "6 (which is 3 times 2) in its place.\r\n" ); document.write( "\r\n" ); document.write( "Also take out the 4(5) and put 20 (which is 4\r\n" ); document.write( "times 5) in its place. Then we have:\r\n" ); document.write( "\r\n" ); document.write( " 6 - 20 + 9\r\n" ); document.write( "\r\n" ); document.write( "Now there is only a subtraction and an addition\r\n" ); document.write( "left to do, so we must do them in the order of\r\n" ); document.write( "left to right. We come to 6 - 20 first, so we \r\n" ); document.write( "do that and get -14. Then we replace 6 - 20 by\r\n" ); document.write( "-14. Then we have\r\n" ); document.write( "\r\n" ); document.write( " -14 + 9\r\n" ); document.write( "\r\n" ); document.write( "Now we do that addition and end up with -5.\r\n" ); document.write( "\r\n" ); document.write( "So the answer is -5.\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |