document.write( "Question 175770This question is from textbook
\n" ); document.write( ": At most 500 feet of fencing is available for a steer pasture(assuming it's a rectangle). Ther is only space for the pasture to be 100 feet wide.
\n" ); document.write( "a. Write a system of two linear inequalities that describe this situation.\r
\n" ); document.write( "\n" ); document.write( " y < or = 100, with y being the width
\n" ); document.write( " 2y + 2x < or equal to 500, which became y < or equal to -x + 250\r
\n" ); document.write( "\n" ); document.write( "b. Graph the system to show all possible solutions.\r
\n" ); document.write( "\n" ); document.write( " Drew a horizontal line on graph at y-axis 100, and shaded below the line.\r
\n" ); document.write( "\n" ); document.write( " Wasn't sure what to do with 2nd equation in graphing, particularly the slope. Feeling really stupid about this. :) :( Thanks for any help possible!
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Algebra.Com's Answer #130864 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"y+%3C=+100\"
\n" ); document.write( "\"2x+%2B+2y+%3C=+500\"
\n" ); document.write( "\"2y+%3C=+-2x+%2B+500\"
\n" ); document.write( "\"y+%3C=+-x+%2B+250\"
\n" ); document.write( "The line you draw on the graph is
\n" ); document.write( "\"y+=+-x+%2B+250\"
\n" ); document.write( "This is in the form
\n" ); document.write( "\"y+=+mx+%2B+b\" where \"m\" is the slope, so
\n" ); document.write( "\"m+=+-1\"
\n" ); document.write( "A slope of \"-1\" is perpendicular to a slope of \"1\"
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-50%2C+300%2C+-50%2C+300+%2C0%2Ax+%2B+100%2C-x+%2B+250%29+\"
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