document.write( "Question 175700: How do I find the system of equations 3y+2z=12 and y-z=9? \n" ); document.write( "
Algebra.Com's Answer #130801 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Start with the given system of equations:\r
\n" ); document.write( "\n" ); document.write( "\"system%283y%2B2z=12%2Cy-z=9%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2%28y-z%29=2%289%29\" Multiply the both sides of the second equation by 2.\r
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\n" ); document.write( "\n" ); document.write( "\"2y-2z=18\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "So we have the new system of equations:\r
\n" ); document.write( "\n" ); document.write( "\"system%283y%2B2z=12%2C2y-2z=18%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now add the equations together. You can do this by simply adding the two left sides and the two right sides separately like this:\r
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\n" ); document.write( "\n" ); document.write( "\"%283y%2B2z%29%2B%282y-2z%29=%2812%29%2B%2818%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283y%2B2y%29%2B%282z%2B-2z%29=12%2B18\" Group like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"5y%2B0z=30\" Combine like terms. Notice how the z terms cancel out.\r
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\n" ); document.write( "\n" ); document.write( "\"5y=30\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%2830%29%2F%285%29\" Divide both sides by \"5\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=6\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"3y%2B2z=12\" Now go back to the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3%286%29%2B2z=12\" Plug in \"y=6\".\r
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\n" ); document.write( "\n" ); document.write( "\"18%2B2z=12\" Multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"2z=12-18\" Subtract \"18\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2z=-6\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"z=%28-6%29%2F%282%29\" Divide both sides by \"2\" to isolate \"z\".\r
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\n" ); document.write( "\n" ); document.write( "\"z=-3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"y=6\" and \"z=-3\".\r
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