document.write( "Question 175691: a 6 passenger plane cruises at 180 mph in calm air. if the plane flies 7 miles with the wind in the same amount of time as it flies 5 miles against the wind, then what is the wind speed?\r
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document.write( "i know that r= d/t \n" );
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Algebra.Com's Answer #130790 by stanbon(75887) ![]() You can put this solution on YOUR website! a 6 passenger plane cruises at 180 mph in calm air. if the plane flies 7 miles with the wind in the same amount of time as it flies 5 miles against the wind, then what is the wind speed? \n" ); document.write( "----------------------- \n" ); document.write( "Withwind DATA: \n" ); document.write( "rate = 180+c ; distance = 7 mi ; time = d/r = 7/(180+c) hrs. \n" ); document.write( "------------------ \n" ); document.write( "againstwind DATA: \n" ); document.write( "rate = 180-c ; distance = 5 mi ; time = d/r = 5/(180-c) hrs. \n" ); document.write( "---------------- \n" ); document.write( "EQUATION: \n" ); document.write( "time = time = 7/(180+c) = 5/(180-c) \n" ); document.write( "Cross-multiply \n" ); document.write( "7(180-c) = 5(180+c) \n" ); document.write( "7*180 - 7c = 5*180+5c \n" ); document.write( "12c = 2*180 \n" ); document.write( "c = 2*15 \n" ); document.write( "c = 30 mph (speed of the wind) \n" ); document.write( "=================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |